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Sorry the caps lock was on. Can you help me with this pre calculus question. I'm not quite sure how to do this. Here are the instructions.

Find the area between each curve and the x-axis for the given interval:

y=2x^2+x+1 from x=3 to x=6


    This looks like integral calculus, so why do they call it precalculus?

    The area is the definite integral of the function y(x) from 3 to 6.

    The definite integral is the change in the indefinite integral going from x=3 to x=6.

    The indefinite integral is
    (2/3)x^3 +x^2/2 + x

    Calculate the value of that function at x=6 and subtract the value at x=3.

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