Math
posted by Victoria .
What would you do...
(4)^(3/square root 2) ÷ 16^(2*square root 2) ?

Math 
drwls
Recognize that
16^(2*square root 2)= (4^2)^(2sqrt2)
= 4^(4sqrt2)
So your expression can be written
4^(3/sqrt2)/4^(4sqrt2)
= 4^[(3/sqrt2)(4sqrt2)]
= 4^[(3/2)sqrt24sqrt2]
= 4^[(5/2)sqrt2]
= 2(5sqrt2)
I might have made a mistake somewhere, so be sure to verify the steps.
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