Question

4t^2-4/9(t+1) * 3t+3/2t-2

Answer 1

Consider [4t^2-4/9(t+1)] * (3t+3)/2t-2

3t+3/2t-2 = 3(t+1)/2(t-1)
(4t^2-4) = 4(t+1)(t-1)

[(4t^2-4)/9(t+1)] * (3t+3)/(2t-2)
= {[4(t+1)(t-1)]/9(t+1)}/[3(t+1)/2(t-1)]

Now start cancelling terms that appear in both denomimnator and numerator.