write the balanced half reaction for the conversion of Cl2(g)to Cl-(aq)
Cl2(g) + 2e + H2O==> 2Cl^-(aq)
although Cl2 reacts with H2O to produce HOCl + HCl OR
I can write two equations to get around that.
Cl2(g) + 2e ==> 2Cl^-
Cl^- + H2O ==> Cl^-(aq)
I don't know what level you are in school so you will need to make the choice of which to use.
i am a sophmore
but i reallyy really suck at chemisrty
i am passing with a c luckily
but the teacher i have is really bad but thanxs soo much DrBob222
The rules you need to work on, if it isn't too late, are as follows:
1. Don't get behind.
2. Understand all you can. Ask questions. See the teacher during office hours. Memorize that which you simply cannot understand.
3. Work the problems at the end of the chapter.
4. Study with someone who can help you.
5. Get a tutor if chemistry is an essential course for your major.
6. Shuck the idea that chemistry is only for smart people. That simply isn't so; otherwise, I would have failed.
7. Adopt a positive attitude. If you convince yourself you will fail, you probably will.
GOOD LUCK.
To write the balanced half-reaction for the conversion of Cl2(g) to Cl-(aq), you need to consider the change in oxidation states of chlorine and balance the number of atoms and charges.
Here's how you can go about it:
Step 1: Write the unbalanced half-reaction for the reduction of Cl2(g) to Cl-(aq).
Cl2(g) + 2e- → 2Cl-(aq)
Note that the reduction half-reaction involves the gain of electrons (reduction) and the formation of chloride ions (Cl-).
Step 2: Balance the number of atoms and charges on both sides of the half-reaction.
To balance the half-reaction, multiply the number of electrons in the reduction half-reaction by a suitable factor, so that the charges are balanced.
In this case, the number of electrons on the left side is 2, so we need to multiply the half-reaction by 2 to balance the charges:
2Cl2(g) + 4e- → 4Cl-(aq)
Now the atoms and the charges are balanced.
Therefore, the balanced half-reaction for the conversion of Cl2(g) to Cl-(aq) is:
2Cl2(g) + 4e- → 4Cl-(aq)