A 4.55L sample of water contains .115g of sodium ions. Determine the concentration of sodium ions in ppm if the density of the solutions is 1.00g/mL.
Ok so ppm=mass of solute/mass of solution *10^-6
so we have the mass of the solute .115g
and for the solution we use 4.55 L and the given density and figure out grams. which I got 4550g
.115g/4550+.115*10^-6=2.53ppm
but the answer is supposed to be 25.3, I'm not sure what I'm doing wrong
Since the density is 1.00 g/mL, that means we can use 1.0 mL = 1.0 g, I remember that 1 mg/L = 1 ppm
So 0.115 g/4.55 L = 0.02527 g/L or that x 1000 = 25.27 mg/L or 25.3 ppm.
Your way:
0.115 g/4550 g + (.115 x 10^-6) =
0.115 g/4550 g + (negligible) =.
2.527 x 10^-5 g/1.0 g.
Then from g/g to g/10^6 g
2.527 x 10^-5 x 10^6/10^6 =
25.27 g/10^6 g = 25.27 ppm = 25.3 ppm
I'm not sure what the 0.115 x 10^-6 does. If you are doing grams, then
0.115/4550 g + 0.115 g = 0.115g/4550 and you can choose to add the 0.115 or not. I think what you want is
0.115 x 10^6/(4550+0.115) = 25.3 ppm which does all of what I did above in one step.
Well, it seems like you forgot to put parentheses around the denominator when calculating the concentration. Let's go through the calculation together:
First, we need to convert the volume of the solution from liters to milliliters:
4.55 L = 4.55 * 1000 mL = 4550 mL
Next, we need to calculate the mass of the solution using the density:
mass of solution = volume of solution * density
mass of solution = 4550 mL * 1.00 g/mL
mass of solution = 4550 g
Now, let's calculate the concentration in ppm:
concentration (ppm) = (mass of solute / mass of solution) * 10^6
concentration (ppm) = (0.115 g / 4550 g) * 10^6
concentration (ppm) ≈ 25.27 ppm (rounded to two decimal places)
So, the concentration of sodium ions in ppm is approximately 25.27 ppm.
To find the concentration of sodium ions in ppm, you need to divide the mass of the solute (sodium ions) by the mass of the solution and then multiply by 10^6.
Given:
Volume of solution (V) = 4.55 L
Density of solution = 1.00 g/mL
Mass of solute (sodium ions) = 0.115 g
First, convert the volume of the solution from liters to milliliters:
V(ml) = V(L) * 1000
V(ml) = 4.55 L * 1000
V(ml) = 4550 mL
Then, calculate the mass of the solution:
Mass of solution = Volume of solution * Density of solution
Mass of solution = 4550 mL * 1.00 g/mL
Mass of solution = 4550 g
Now, calculate the concentration in ppm:
Concentration (ppm) = (Mass of solute / Mass of solution) * 10^6
Concentration (ppm) = (0.115 g / 4550 g) * 10^6
Concentration (ppm) = 2.527 ppm
So the concentration of sodium ions in ppm is approximately 2.53 ppm, not 25.3 ppm as you mentioned. Please double-check the correct answer.
To determine the concentration of sodium ions in ppm, you need to correctly calculate the mass of the solution. Here's how to do it step by step:
1. Given that the density of the solution is 1.00g/mL, we can convert the volume of the solution from 4.55L to grams.
4.55L * 1.00g/mL = 4550g
2. Now, let's calculate the concentration of sodium ions in ppm using the formula you mentioned:
ppm = (mass of solute / mass of solution) * 10^6
mass of solute = 0.115g (given)
mass of solution = 4550g (calculated)
ppm = (0.115g / 4550g) * 10^6
ppm ≈ 25.27
So, the concentration of sodium ions in the water sample is approximately 25.3 ppm. It seems there was a calculation error in your previous attempt.