How many grams of KCl can you dissolve in 50. g of water at 70 degrees C?
You can't draw a graph on these boards but if its a table, can you either describe it or list the columns and temperatures?
You can't type information on this board in columns but you can do it this way, using periods for spaces
T........mass KCl/100 mL
10........a grams.
20........b grams
30........c grams
etc.
So, for KCl, using the graph...
T.....mass KCl/100 mL
10....30
20....32 or 33
30....35
40....38
50....41
60....44
70....46
80....49
90....52 or 53
100...56
Is the solubility of KCl then 46 grams/100 mL at 70 degrees C? (I don't know if that is the unit for you OR if you were just copying the unit I gave as an example.) If 46 g/100 mL, then
g in 50 mL = 46 x (50 mL/100 mL) = 23 g/100 mL.
To determine how many grams of KCl can be dissolved in 50 g of water at 70 degrees Celsius, we need to refer to the solubility chart or table specific to KCl at that temperature.
The solubility of a substance in a given solvent generally increases with temperature. In this case, we need to find the solubility of KCl in water at 70 degrees Celsius.
One way to find this information is by referring to solubility tables or handbooks that provide solubility data for various substances. These references typically provide the solubility in grams of solute that can be dissolved in 100 grams of solvent at a specific temperature.
Let's assume that the solubility of KCl in water at 70 degrees Celsius is 56 g/100 g of water. This means that in 100 g of water at that temperature, 56 g of KCl can be dissolved.
To determine how many grams of KCl can be dissolved in 50 g of water, we can use a proportion:
(56 g KCl / 100 g water) = (x g KCl / 50 g water)
Cross-multiplying and solving for 'x,' we get:
x g KCl = (56 g KCl / 100 g water) * (50 g water)
x g KCl = 28 g KCl
Therefore, you can dissolve 28 grams of KCl in 50 grams of water at 70 degrees Celsius.
You must have a table in your text or in your lab manual that gives the solubility of some of the salts at various temperatures. . I assume this is an experiment you are conducting. KCl is rather soluble.
In the question above this one it says refer to a solubility chart, but my professor never taught us how to answer these questions while using a solubility chart so I have no idea what to do. I've tried going to his office hours for help, but he's only there when I have a class.
It's the standard solubility chart (if you looked it up on google or something) but I have no idea how to answer the question.