physics

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If you drop a stone into a well that is d = 128.0 m deep, how soon after you drop the stone will you hear it hit the bottom of the well?

  • physics -

    g = acceleration = -9.8 m^s^2
    z = height = zo - Vo t - (1/2)(9.8)t^2
    z = final height = -128
    zo = initial height = 0
    Vo = starting velocity = 0
    so
    -128 = -4.9 t^2
    t^2 = 128/4.9
    t = 5.11 seconds

  • physics -

    Since the sound still needs to travel back up the well, it will actually take longer than 5.11 seconds.

    v=d/t

    343=128/t

    t=0.37

    5.11+0.37=5.48 seconds.

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