maths
posted by kim .
HI THERE, COULD SOME ONE PLEASE HLEP ME ON THIS QUESTION...
A sample of the nearground air concentration of caesium137 at
11 locations in southern Germany a few days after the Chernobyl nuclear
accident in 1986 consisted of the following measurements (in Bq/m3).
5.77
3.30
7.98
8.29
4.85
2.90
1.74
0.05
0.23
0.60
4.98
1)Choose the option that gives the median concentration within the
sample.
Options for Question 1
A) 0.60 B) 2.90 C) 3.10
D) 3.30 E) 3.70 F) 5.77
2)Choose the option that gives the lower quartile for the nearground air
concentration within the sample.
3)Choose the option that gives the upper quartile for the nearground
air concentration within the sample.
Options for Questions 2 and 3
A) 0.23 B) 0.60 C) 1.74 D) 3.30
E) 4.98 F) 5.77 G) 7.98 H) 8.29

Arrange the scores in order of their value. In this order, the sixth value will be the median — 50% (half) of the scores will have a higher value and 50% will have a lower value. If there are two middlemost scores, the median would be the mean of those two scores.
The lowest quartile is the lowest 25% or lowest quarter. 11/4 = 2.75, so 2.75 or rounded to 3, would be the number of scores in the lowest quartile.
At the high end, the same would be true of the highest quartile.
I hope this helps. Thanks for asking.