# trig

posted by Priya

Solve the given triginometric equation analytically. Use values of of x for 0 less than or equal to x less than 2pi

sin^2x - 2sinx = 1

How do I get towards the answer of 3.569, 5.856

Thank you again

1. Reiny

hint:
sin^2 x - 2sinx - 1 = 0

I got sinx = 1-√2 or sinx = 1+√2 (too big, sine has to be ≤ 1)

from sinx = 1-√2 = -.4142 x must be in quad III or IV

related acute angle in radians is .427

in III x = .427 + pi = 3.569
in IV x = 2pi - .427 = 5.856

can you take it from here?

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