algebra2
posted by brit .
(3b2)/b+1=4(b+2/b1)
please help

Multiply both sides by b. (I am assuming that (b+1) and (b1) are not denominators.)
3b2+b = 4bb(b+2/b1)
3b2+b = 4bb^22+b
(b^2 = b squared.)
Combine like terms.
2b2 = 5bb^22
Add 2 to both sides.
2b = 5bb^2
Bring all terms to the left side of the equation.
b^23b = 0
Factor.
b(b3) = 0
Therefore b = 3 or 0.
I hope this helps. Thanks for asking.
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