a concave mirror of diameter 40m is used with a 6cm tall object placed 20 cm from it. Where is the image?
Can you check my solution
Radius(R)=20cm
Distance object(do)=20cm
(2/R)=(1/do)+(1/di)
(1/di)=(2/R)-(1/do)
why do they give you the object height i don't think you need to use it?
Responses
To find the location and characteristics of the image formed by a concave mirror, you will need to use the mirror equation:
(1/do) + (1/di) = 2/R,
where:
- do is the object distance from the mirror (in this case, 20 cm),
- di is the image distance from the mirror (what we are trying to find),
- R is the radius of curvature of the mirror (in this case, 20 cm).
Since the object distance and the radius of curvature are both positive, the image distance will also be positive (indicating that the image is formed on the same side as the object).
Plugging in the values into the equation:
(1/20) + (1/di) = 2/20,
1/di = 2/20 - 1/20,
1/di = 1/20,
di = 20 cm.
So, the image is formed 20 cm away from the concave mirror.
Regarding your question about the object height, in this particular case, the object height was not used because you were seeking the location of the image. The object's height is required when calculating the magnification of the image or determining its size, but it is not necessary to find the location of the image.