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chem again

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Use Charles Law to solve for the missing value of each of the following a) 80.0 mL, T1= 27 degrees C, T2=77 degrees C. V2 =?
b)V1= 125 L, V2=85.0L T2=127degrees C T1=?
c) T1=-33degrees C V2=54.0mL, T2=160.0 degrees C V1=?

can somebody help me with atleast a and do step by step so i can understand how to do b and c

  • chem again -

    Charles' Law is
    V1/T1 = V2/T2
    T must be in Kelvin.

  • chem again -

    80.0 = 27
    77= ???
    right

  • chem again -

    Do you know what Kelvin is? Why do you persist in using degrees C when it must be changed to Kelvin. The formulas don't work with C. They work only with Kelvin.

  • chem again -

    i don't know how to.. that's why i asked could if u could just help me step with step with how to do A. that way if i could see what i'm missing i could do the others and know how to do other questions.

  • chem again -

    Use Charles Law to solve for the missing value of each of the following a) 80.0 mL, T1= 27 degrees C, T2=77 degrees C. V2 =?
    b)V1= 125 L, V2=85.0L T2=127degrees C T1=?
    c) T1=-33degrees C V2=54.0mL, T2=160.0 degrees C V1=?


    80 mL....27 C. Kelvin = 27 + 273= 300 K.
    V2.......77 C. Kelvin = 77 + 273= 350 K.

    80/300 = V2/350
    Cross multiply.
    80*350 = 300*V2
    Solve for ??
    V2 = 80*350/300 = 93.3 mL
    Check my arithmetic.
    Check my work.

  • chem again -

    i attempted to do b and c can you tell me if i did it right?

    125...... T1
    85.0 ....127 Kelvin 127+ 273= 358

    125= 85
    T1=358
    125*358/85= 526.5

    for C i did
    V1... -33 C Kelvin -33+273=240
    54.0ml....160 C Kelvin 160+273=433
    V1=54
    240=433
    54*240/433=29.9
    T1

  • chem again -

    c is ok.
    b would be ok but you made an error in adding 127 + 273. My calculator gives me 400 and not 358. I THINK you added in 85 which is V2 and not 127 for T2.

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