A system undergoes a two-step process. In the first step, the internal energy of the system increases by 368 J when 144 J of work is done on the system. In the second step, the internal energy of the system increases by 24 J when 248 J of work is done on the system.

(a) For the overall process, what is the heat?
J

(b) What type of process is the overall process?
Isobaric
Isochoric
Isothermal
Adiabatic

I'm thinking owuld add the levels of heat, but I'm not sure of what formula to used and I think the process would be Isochronic

To determine the heat for the overall process, we need to apply the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.

(a) To find the heat for the overall process, we can add the heats for each step of the process:

Heat = Heat1 + Heat2

For the first step, the internal energy of the system increases by 368 J when 144 J of work is done on the system. Since no information is given about heat, we can assume that the heat for this step is zero, as work done can increase the internal energy without any heat transfer.

Therefore, Heat1 = 0 J.

For the second step, the internal energy of the system increases by 24 J when 248 J of work is done on the system. Again, no information is given about heat, so we assume it is zero.

Therefore, Heat2 = 0 J.

Now, we can calculate the heat for the overall process:

Heat = Heat1 + Heat2
= 0 J + 0 J
= 0 J

Hence, the heat for the overall process is 0 J.

(b) To determine the type of process, we need to analyze the work done in each step.

In the first step, 144 J of work is done on the system, but there is no change in volume mentioned. This indicates that the process is not isochoric (constant volume) since no work would be done in that case. So, the first step cannot be isochoric.

In the second step, 248 J of work is done on the system, but there is no mention of any change in pressure. This rules out the isobaric (constant pressure) process since work done in an isobaric process is directly related to the change in pressure.

Now, we are left with two options: isothermal and adiabatic.

In an isothermal process, the temperature of the system remains constant. Since no information is given about temperature, we cannot conclude that the process is isothermal.

Therefore, the overall process is more likely to be adiabatic, which means no heat is exchanged with the surroundings.

In summary, the overall process has a heat of 0 J and is likely to be an adiabatic process.