How many grams of NaOH are present in 5.0 mL of a 1.0% (m/v) NaOH solution?

Ans

5kg

To find the number of grams of NaOH present in the given solution, you'll need to use the equation:

Mass (grams) = Volume (mL) x Concentration (g/mL)

Let's break down the given information:

Volume = 5.0 mL
Concentration = 1.0% (m/v)

First, convert the concentration from a percentage to a decimal.

1.0% = 1.0 / 100 = 0.01

Next, substitute the values into the equation:

Mass (grams) = 5.0 mL x 0.01 g/mL

Multiply the volume and concentration:

Mass (grams) = 0.05 grams

Therefore, there are 0.05 grams of NaOH present in 5.0 mL of a 1.0% (m/v) NaOH solution.

The term 1% NaOH (m/v) means 1 g NaOH in 100 mL solution. 1g/100 mL then gives you the g/mL and that x 5 gives you the g in 5 mL.