Multiply

sq rt5(3sq rt3-5sq rt9)

my answer is 3sq rt15 - 15sq rt5
is this correct? Thanks

1 answer

correct

Similar Questions

perform the indicated operation(-4)3sq

Top answer: 3 squared = 9 Multiply: -4 * 9 = ? Read more.
(2sq root 5 + 3sq root 7)(2sq root 5 + 3sq root 7)

Top answer: Using the distributive property: (2sq root 5 + 3sq root 7)(2sq root 5 + 3sq root 7) = 4(5) + 2(2sq Read more.
what is the simplified form of3sq rt 5c * sq rt 15c^3? A.15c^2 sq rt 3 B.6c^2 sq rt 5 c.5c^2 sq rt 3 d.12c^4sq rt 5 I think it

Top answer: A is correct answer Read more.
Point E is the midpoint of BC of a rectangle ABCD and F is the mid point of CD, The area of Triangle AEF is 3sq.units then the

Top answer: Make your sketch. let EC = x , FC = y then (1/2)(x)(y) = 3 xy = 6 area of ABCD = 2x(2y) = 4xy = 24 Read more.
If tan x = -sq rt3/3 and cos x = -sq rt3/2, the measure of <x is?

Top answer: Use a unit circle and special triangles. At 5pi/6 on a unit circle, cosx= -sqrt3/2 and sinx=1/2. Read more.
Please check all of my answers for all the questions. Simply reply with correct or incorrect, and if incorrect, provide the

Top answer: Correct Read more.
Whats the CORRECT answerQuestion 9 (1 point) Which answer shows the correct steps to solve the equation a Subtract 4 from both

Top answer: There is no given equation to solve. The question cannot be answered without an equation to solve. Read more.
When multiplying two numbers written in scientific notation what do you do with the exponents of the 10?A. multiply B. add C.

Top answer: So the answer is B? Read more.
can someone correct these for me please...Remove the parentheses. -(3x+5y) My answer: -3x-5y Find the value of the polynomial

Top answer: You're welcome! I'm glad to hear that your answers are correct. It's always a good idea to Read more.
A classmate asks you to check their answer to this problem:Simplify: a3b5a2b−3 They got a6b−15 as their final answer. Are

Top answer: No, the answer is not correct. When the bases are being multiplied, you need to add the exponents. Read more.