If the distance between two slits is .05mm and the distance to the screen is 2.5m find the spacing between the first and second order bright fringees for yellow light of wavelenght 600nm.
d=5x10^-5m
L=2.5m
wavelength= 6x10^-7m
x=?
x=wavelength*L/d
=(6x10^-7)(2.5)/5x10^-5m
=.03m
I am not sure if this is correct. Is .03m too big?
To find the spacing between the first and second order bright fringes, you can use the formula:
x = (λL) / d
where:
- x is the spacing between the fringes
- λ is the wavelength of the light
- L is the distance from the slits to the screen (2.5m in this case)
- d is the distance between the slits (0.05mm or 5x10^-5m in this case)
First, let's convert the distance between the slits to meters:
d = 0.05mm = 0.05×10^-3m = 5×10^-5m
Now substitute the values into the formula:
x = (λL) / d
= (600nm) × (2.5m) / (5×10^-5m)
= (600×10^-9m) × (2.5m) / (5×10^-5m)
= (600 × 2.5) / 5
= 300 / 5
= 60
The spacing between the first and second order bright fringes is 60 units (meters).
Therefore, the correct answer is x = 60m, not 0.03m.