how to write this as a net ionic equation?
Al(s)+ H2SO4(aq)
Al + 2H^+ + SO4^= ==>Al^+3 + SO4^= + H2
The sulfate ions cancel. The others do not. You may want to balance it.
To write a net ionic equation, you need to break down the reactants and products into their respective ions and eliminate the spectator ions. Here's how you can write the net ionic equation for the reaction between aluminum (Al) and sulfuric acid (H2SO4):
Step 1: Write the balanced molecular equation
Al(s) + H2SO4(aq) → Al2(SO4)3(aq) + H2(g)
This is the balanced equation representing the overall reaction.
Step 2: Dissociate the strong electrolytes
The reactants and products that are strong electrolytes should be dissociated into their ions:
Al(s) remains unchanged since it is a solid.
H2SO4(aq) dissociates into H+(aq) and SO4^2-(aq).
Al2(SO4)3(aq) dissociates into 2 Al^3+(aq) and 3 SO4^2-(aq).
H2(g) remains unchanged since it is a gas.
Step 3: Identify the spectator ions
Spectator ions are the ions that are present on both sides of the equation and do not participate in the chemical reaction. In this case, the H+ and SO4^2- ions can be identified as spectator ions because they are present on both sides.
Step 4: Write the net ionic equation
After removing the spectator ions, the remaining ions form the net ionic equation. In this case, the net ionic equation is:
Al(s) + 3 H+(aq) → Al^3+(aq) + H2(g)
So, the net ionic equation for the reaction between aluminum (Al) and sulfuric acid (H2SO4) is Al(s) + 3 H+(aq) → Al^3+(aq) + H2(g).
To write the net ionic equation for the reaction between aluminum (Al) and sulfuric acid (H2SO4), you need to first write the balanced molecular equation and then convert it into the net ionic equation.
Step 1: Write the balanced molecular equation
The balanced molecular equation for the reaction between aluminum and sulfuric acid is:
2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3H2(g)
Step 2: Identify the ions
Next, you need to identify the ions that are present in the solution both before and after the reaction.
Before the reaction:
Al(s) → No ions present (solid metal)
H2SO4(aq) → H+(aq) + SO4^2-(aq)
After the reaction:
Al2(SO4)3(aq) → 2Al^3+(aq) + 3SO4^2-(aq)
H2(g) → No ions present (gaseous element)
Step 3: Write the net ionic equation
Now, you can write the net ionic equation by eliminating the spectator ions (ions that appear on both sides of the equation). The spectator ions in this case are H+ and SO4^2-.
Net Ionic Equation:
2Al(s) + 6H+(aq) → 2Al^3+(aq) + 3H2(g)