precalculuscheck over work
posted by riya .
1). change to exponential form:
log2^256=8; 2^8=256
log0.0001=4; 10^4=0.0001
2). change to logarithmic form:
5^3=125; log5^125=3
4^3=1/64; log4^1/64=3
3). solve the equation:
3^(x2)=27^(x+1)
3^(x2)=(3^3)^(x+1)
3^(x2)=3^(3x+3)
x2=3x+3
5=2x
5/2=x
2^(x^(2)+1)=4^(x+2)
2^(x^(2)+1)=(2^2)^(x+2)
2^(x^(2)+1)=2^(2x+4)
x^(2)+1=2x+4
x^(2)2x3
(x+1)(x3)
x=1;x=3

all correct.