What is the net ionic equation for the following reaction?FeCl3(aq)+3LiOH(aq)
-> Fe(OH)3(s)+3LiCl(aq)
The chloride and lithium ions stay in solution, no net change.
Fe+++ + 3OH- >> Fe(OH)3
Fe3+ +3Oh- -> Fe (OH)3
To determine the net ionic equation for the given reaction, we need to first write the balanced molecular equation.
The balanced molecular equation for the given reaction is:
FeCl3(aq) + 3LiOH(aq) -> Fe(OH)3(s) + 3LiCl(aq)
Now, let's break down the equation into its respective ions and identify the spectator ions.
FeCl3(aq) breaks down into Fe3+(aq) and 3Cl-(aq).
LiOH(aq) breaks down into Li+(aq) and OH-(aq).
The complete ionic equation is:
Fe3+(aq) + 3Cl-(aq) + 3Li+(aq) + 3OH-(aq) -> Fe(OH)3(s) + 3Li+(aq) + 3Cl-(aq)
Now, let's cancel out the spectator ions, which are Li+ and Cl- on both sides of the equation.
Fe3+(aq) + 3OH-(aq) -> Fe(OH)3(s)
Therefore, the net ionic equation for the reaction FeCl3(aq) + 3LiOH(aq) -> Fe(OH)3(s) + 3LiCl(aq) is:
Fe3+(aq) + 3OH-(aq) -> Fe(OH)3(s)
To write the net ionic equation for a reaction, you need to first write the balanced molecular equation, and then break down the compounds into their respective ions. Finally, you can cancel out the spectator ions to obtain the net ionic equation.
Let's start by writing the balanced molecular equation for the reaction:
FeCl3(aq) + 3LiOH(aq) → Fe(OH)3(s) + 3LiCl(aq)
Next, break down each compound into its ions based on their solubilities:
FeCl3(aq) dissociates into Fe3+ and 3Cl- ions.
LiOH(aq) dissociates into Li+ and OH- ions.
Fe(OH)3 is an insoluble solid and remains in its molecular form in this reaction.
LiCl(aq) dissociates into Li+ and Cl- ions.
Now, write the complete ionic equation by representing the dissociated ions:
Fe3+(aq) + 3Cl-(aq) + 3Li+(aq) + 3OH-(aq) → Fe(OH)3(s) + 3Li+(aq) + 3Cl-(aq)
Finally, cancel out the spectator ions (ions that appear on both sides of the equation), which are Li+ and Cl-, to obtain the net ionic equation:
Fe3+(aq) + 3OH-(aq) → Fe(OH)3(s)
So, the net ionic equation for the given reaction is:
Fe3+(aq) + 3OH-(aq) → Fe(OH)3(s)