# maths

posted by .

Is this right, and where do i go from here???
solve p-1/2-p-2/3=1
(3p-3)-(2p-4)/6=1

• maths -

The way you put it, there's no multiplication... so I don't know where you get 3p and 2p... maybe you want to revise your original problem by addiing in the parentheses.

Anyway, by the way you put it... it should be:
p-p-1/2-2/3=1 (combine like-terms)
0-3/6-4/6=1 (common denominator)
-7/6=1 (subtraction)

... and you end up with a false statement, yep, you need to revise your problem so people can read it correctly.

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