using only the periodic table, write the expected ground-state electron configurations for:
a. element number 116
b. an element with three unpaired 5d electrons
c. the halogen with electrons in the 6p atomic orbitals
i still don't understand.
especially part a, because element number 116 is not on the periodic table.
http://www.webelements.com/
a. Element number 116 is Livermorium (Lv). To determine its expected ground-state electron configuration, we can look at its position in the periodic table. Livermorium is located in Group 16, also known as the Chalcogens. Each element in this group typically has 6 valence electrons. Therefore, the expected ground-state electron configuration for Livermorium is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰ 6p⁶.
b. To find an element with three unpaired 5d electrons, we need to look at elements in the 5d block of the periodic table. One such element is Ruthenium (Ru), which has an atomic number of 44. Therefore, the expected ground-state electron configuration for an element with three unpaired 5d electrons is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d⁷ 5p⁶.
c. The halogen with electrons in the 6p atomic orbitals is Astatine (At). It is located in Group 17, also known as the Halogens. Atoms in this group typically have 7 valence electrons. Therefore, the expected ground-state electron configuration for Astatine is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵ 6s² 4f¹⁴ 5d¹⁰ 6p⁵.
To determine the expected ground-state electron configurations using only the periodic table, you need to know the order in which electrons fill the atomic orbitals. Here are the steps to follow for each part of the question:
a. Element number 116:
Start by finding element number 116 on the periodic table. 116 is the atomic number for Livermorium (Lv). To determine Lv's expected ground-state electron configuration:
1. Locate the row corresponding to Lv (in this case, it is row 7).
2. Start filling the orbitals in order of increasing energy, following the Aufbau principle. The Aufbau principle states that electrons fill atomic orbitals in order of increasing energy, from the lowest energy level to the highest.
- The 1s orbital is the lowest energy level, followed by the 2s, 2p, 3s, and so on.
3. It can be noted that Lv belongs to the period 7, indicating that the outermost shell is the 7th shell (n = 7).
By following these steps, the expected ground-state electron configuration for element number 116 (Livermorium) is: [Rn] 5f14 6d10 7s2 7p4.
b. An element with three unpaired 5d electrons:
For an element to have three unpaired 5d electrons, it belongs to the d-block of the periodic table. The d-block starts at period 4. By locating the element within the d-block and following the filling order for orbitals:
1. Locate the d-block on the periodic table.
2. Find an element in the d-block that corresponds to the electron configuration with three unpaired 5d electrons.
For example, Rhodium (Rh) is an element in the d-block that has three unpaired 5d electrons. The expected ground-state electron configuration for Rhodium is: [Kr] 5s2 4d8.
c. The halogen with electrons in the 6p atomic orbitals:
Halogens belong to group 17 (VIIA) of the periodic table. To find the halogen with electrons in the 6p atomic orbitals:
1. Look for the elements in group 17 (VIIA).
2. Determine the element that belongs to period 6 (row 6) to have electrons in the 6p atomic orbitals.
The element that fits these criteria is Iodine (I). The expected ground-state electron configuration for Iodine is: [Kr] 5s2 4d10 5p6.