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A woman with mass 50.0kg is standing on the rim of a large disk that is rotating at 0.500rev/s about an axis perpendicular to it through its center. The disk has a mass of 110kg and a radius of 4.00m. Calculate the magnitude of the total angular momentum of the woman-plus-disk system, assuming that you can treat the woman as a point.

  • physics -

    M = 110
    m = 50
    r = 4
    The moment of inertia of the disk about the axis is .5 M r^2
    The moment of inertia of the woman about the axis is m r^2
    Total moment of inertia I = .5 Mr^2 + m r^2
    angular velocity w = 2 pi * .5 radians/second

    angular momentum = I w = [.5 M + m] r^2* (2 pi *.5)

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