Find the set of all integers, n, for which the fraction
20/(10-n*n) is an integer
I used n*n for n squared
I figured that 10-n*n must be a factor of 20 and the only answer that ended up working was +-3, is this right?
20/(10 -n^2) must be 20, 10, 5, 4 , 2 or 1, with n an integer.
n can only be +/- 3 or 0.