1)A current-carrying conductor is kept at right angles to the direction of a magnetic field. What happens to the force acting on the wire if the strength of the magnetic field doubles?
the force is doubled.
2)How much current is required to produce a force of 0.96 N on a 75 cm long wire oriented at right angles to a 0.24 T magnetic field?
I=F/BL
0.96/0.24*75
I= 0.050 A
yes on both.
To determine the force acting on the wire, we can use the equation for the magnetic force on a current-carrying wire:
F = BIL
where F is the force, B is the strength of the magnetic field, I is the current flowing through the wire, and L is the length of the wire in the magnetic field.
1) In the first question, if the strength of the magnetic field doubles, we can conclude that the force acting on the wire will also double. This is because the magnetic force is directly proportional to the strength of the magnetic field. So, when the field strength doubles, the force acting on the wire will also double.
2) To find the current required to produce a force of 0.96 N on a 75 cm long wire oriented at right angles to a 0.24 T magnetic field, we can rearrange the formula:
I = F / (BL)
Substituting the given values:
I = 0.96 N / (0.24 T * 0.75 m)
I ≈ 0.050 A (rounded to three decimal places)
Therefore, a current of approximately 0.050 A is required to produce a force of 0.96 N on the wire.