Math (Trig)
posted by mtd .
sorry, another I can't figure out
Show that (1cot^2x)/(tan^2x1)=cot^2x
I started by factoring both as difference of squares. Would I be better served by writing in terms of sine and cosine? Such as:
[1(cos^2x/sin^2x)]/[(sin^2x/cos^2x)1]=(cos^2x/sin^2x)

I don't think your equation is an identity,
I tried several angles and the Left Side is not equal to the Right Side.
Check your typing.
In general, I try to prove these type of identities by changing everything to sines and cosines, unless I can recognize one of the common trig relationships. 
let me try to type it out again, my apologies.
Original problem isProve the following:
1 cot^2 x
 = cot^2 x
tan^2 x  1
That is how the problem actually looks.