Carlos has the slow to go hiccups. When they started, he hiccuped after 1 minute had elpased, then again after 2 minutes, again after 4 minutes, next after 8 minutes, and so on. How many total hiccups did he hiccup in the month of April if they began 12 midnight, april 1st?

wat is the slow to go hiccups???

lol, they come slower and slower.

15, anybody?

April has 30 days with 24 hours in each day and 60 minutes in each hour. Use this to get the total minutes.

The interval is doubling, so it very quickly gets into large numbers

1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, ecteras.

Count one hiccup for each doubling until you get to the total minutes.

I hope this helps a little more. Thanks for asking.

thx a lot, 15 was the correct answer

To find the total number of hiccups Carlos had in the month of April, we need to determine how many hiccups he had each day and then sum them up for the entire month.

Let's break it down:

On the first day (April 1st), Carlos had 1 hiccup after 1 minute.
On the second day (April 2nd), Carlos had 2 hiccups (1 hiccup after 2 minutes and another hiccup after 4 minutes).
On the third day (April 3rd), Carlos had 4 hiccups (1 hiccup after 8 minutes, another after 16 minutes, and two more after 32 minutes).
This pattern continues, with Carlos doubling the number of hiccups each day.

To calculate the number of hiccups Carlos had each day, we can use the formula:

Number of hiccups = 2^(Day - 1)

Now, let's calculate the number of hiccups for each day of April:

April 1st: 2^(1-1) = 2^0 = 1 hiccup
April 2nd: 2^(2-1) = 2^1 = 2 hiccups
April 3rd: 2^(3-1) = 2^2 = 4 hiccups
April 4th: 2^(4-1) = 2^3 = 8 hiccups
...
April 30th: 2^(30-1) = 2^29 = 536,870,912 hiccups

We can now sum up the number of hiccups for each day to find the total number of hiccups in April:

Total hiccups = 1 + 2 + 4 + 8 + ... + 536,870,912

To calculate this sum efficiently, we can use the formula:

Sum of geometric series = (first term * (1 - common ratio^n)) / (1 - common ratio)

In this case, the first term is 1, the common ratio is 2, and n is the number of days in April (30).

Total hiccups = (1 * (1 - 2^30)) / (1 - 2)
= (1 * (-1,073,741,823)) / (-1)
= 1,073,741,823

Therefore, Carlos had a total of 1,073,741,823 hiccups in the month of April.