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Strychnine, C21H22N2O2(aq) is a weak base but a powerful poison. Calculate the pH of a 0.001 mol/L solution of strychnine. The Kb of strychnine is 1.0 x 10^-6

My work:

I called Strychnine SN

SN + HOH --> SNH+ + OH-

Kb = (SNH+)(OH-)/(SN)
(SNH+) = x
(OH-) =x
(SN) = 0.001-x

Plugging into Kb

Kb = (x)(x)/(0.001-x)

Can someone please solve for x = (OH-)?

Thank you

  • chemistry -

    See above.

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