A solution is prepared by dissolving 17.1grams of sucrose, c12h22o11, in 275grams of h20.

a)what is the molar mass of sucrose?

I know the formula to use, but can someone show me how do to it, by actually plugging in the numbers.

Answered above.

To find the molar mass of sucrose (C12H22O11), you need to add up the atomic masses of all the elements in its chemical formula.

Here's how you can calculate it step by step:

1. Start by finding the atomic mass of each element in the periodic table:
- The atomic mass of carbon (C) is 12.01 g/mol.
- The atomic mass of hydrogen (H) is 1.01 g/mol.
- The atomic mass of oxygen (O) is 16.00 g/mol.

2. Multiply the atomic mass of each element by the number of atoms in the formula:
- For carbon (C), there are 12 atoms in the formula (C12), so the contribution to the molar mass is 12.01 g/mol × 12 atoms = 144.12 g/mol.
- For hydrogen (H), there are 22 atoms in the formula (H22), so the contribution to the molar mass is 1.01 g/mol × 22 atoms = 22.22 g/mol.
- For oxygen (O), there are 11 atoms in the formula (O11), so the contribution to the molar mass is 16.00 g/mol × 11 atoms = 176.00 g/mol.

3. Add up the contributions from each element to find the molar mass of sucrose:
Molar mass of sucrose = 144.12 g/mol + 22.22 g/mol + 176.00 g/mol = 342.34 g/mol.

Therefore, the molar mass of sucrose (C12H22O11) is 342.34 g/mol.