Post a New Question

Physics

posted by .

The second hand and the minute hand on one type of clock are the same length L.
--------------------------------------------------------------------------------

(a) What is the period Tsecond of the motion of the second hand? (_) The period is 10 seconds.
(o) The period is 60 seconds.
(_) The period is 30 seconds.
(_) The period depends on the value for the length L.
(_) The period is 1 second.

Correct. The period is the time it takes for the second hand to make one complete revolution.



(b) What is the period Tminute of the motion of the minute hand? (_) The period is 600 seconds.
(o) The period is 3600 seconds.
(_) The period is 60 seconds.
(_) The period depends on the value for the length L.
(_) The period is 1800 seconds.

Correct. The period is the time it takes for the minute hand to make one complete revolution.




(c) What is the algebraic expression for the ratio ac,second/ac,minute of the centripetal accelerations for the tips of the second hand and the minute hand? Express your answer in terms of the periods Tsecond and Tminute. (Answer using T_m to be the period of the second hand and T_s to be period of the minute hand.)
ac,second/ac,minute =

not sure what algebraic expression means

(d) What is the ratio ac,second/ac,minute of the centripetal accelerations for the tips of the second hand and the minute hand?
ac,second/ac,minute = I'm thinking the ratio would be T_m/T_s. I sthis correct?

I was able to answer the multiple question part of the problem, but not sure what it is asking me to do about the algebraic expression and ratio

  • Physics -

    c) An agebraic expression is a formula. In this case it is
    a = V^2/R = (2 pi R/T)^2/R
    or
    a = 4 pi^2 R/T^2
    Where R is the length of the clcok's hand.

    (4) The are asking for an algebraic expression for the ratio

    (ac,second)/(ac,minute)

    Assuming the lengths R of the two hands are the same, that would be
    = (T_m/T_s)^2
    because the acceleration is inversely proportional to T^2

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. PreCalc

    Consider the tip of each hand of a clock. Find the linear velocity in millimeters per second for each hand. a. second hand which is 30 millimeters. b. minute hand which is 27 millimeters long. c. hour hand which is 18 millimeters long. …
  2. Physics

    What is the algebraic expression for the ratio ac,second/ac,minute of the centripetal accelerations for the tips of the second hand and the minute hand?
  3. Physics

    What is the algebraic expression for the ratio ac,second/ac,minute of the centripetal accelerations for the tips of the second hand and the minute hand?
  4. Physics

    What is the algebraic expression for the ratio ac,second/ac,minute of the centripetal accelerations for the tips of the second hand and the minute hand?
  5. physics (centripetal acceleration)

    The second hand and the minute hand on one type of clock are the same length. Find the ratio (ac,second/ac,minute) of the centripetal accelerations of the tips of the second hand and the minute hand.
  6. Physics

    A clock has a second hand whose tip rubs against the inside of the glass cover. If the frictional force between the glass cover and the tip of the second hand is 0.0020 N and the length of the hand is 9.5 cm, what is the minimum torque …
  7. physics

    A clock has a second hand whose tip rubs against the inside of the glass cover. If the frictional force between the glass cover and the tip of the second hand is 0.0010 N and the length of the hand is 6.5 cm, what is the minimum torque …
  8. Math (PreCalculus)

    The second hand of a clock is 4 inches long. Describe the height of the tip of the second hand from the bottom of a clock. (The radius of the clock is 1 inch more than the length of the second hand.)
  9. Math

    Which hand has covered more distance from the 12 on a clock, the minute hand at 4:00 or the second hand at 15 seconds past?
  10. Physics

    A clock has a second hand which rubs against the inside of the glass cover. If the frictional force between the glass cover and the tip of the hand is 0.0020 N and the length of the hand is 8 cm, what minimum torque must be supplied …

More Similar Questions

Post a New Question