Sin(30)=5/c
I don't get how to solve.... do you do
5= Sin(30)c? Then what?
Hahaha really helpful ;/.
Anyways I would draw the triangle which is a 30, 60, 90 triangle. 5 is the leg opposite of 30 degrees. The hypotenuse which is c is always 2 times larger than the leg opposite of the 30 degrees in a 30, 60, 90 triangle. So the hypotenuse, c, is 10
Or you can draw a basic 30, 60, 90 triangle. The leg opposite of 30 is 1, opposite of 60 sqrt(3) and hypotenuse is 2. Taking the sin(30) is taking the length of the leg opposite of the 30 angle and dividing it by the length of the hypotenuse. Which is 1/2. So sin(30) is 1/2 and the your equation becomes:
5 = c/2
c = 10.
I believe there are other methods but I think I forgot them *shrug*.
thank you so much!!!
You're very welcome.
To solve for c in the equation sin(30) = 5/c, you can use the cross-multiplication method.
1. Start by multiplying both sides of the equation by c to eliminate the denominator:
c * sin(30) = 5.
2. Now, to solve for c, divide both sides by sin(30):
c = 5 / sin(30).
So to find the value of c, you'll need to evaluate 5 / sin(30).