Carol and Bruno drag a box of mass 58.0 kg along a frictionless floor. Carol pushes the box with a force of 11.4 N at an angle of 40.0 downward from the horizontal. Bruno pulls the
box from the other side with a force of 11.0 N at an angle of 40.0 above the horizontal. What is the net work done on the box if the displacement of the box is 14.5 m?
w=fdcos
11.4(14.5)cos40 get that value and add that to 11.0(14.5)cos40
answer: 2.49 x 10^2 J
WE DONT TALK ABOUT BRUNO
To find the net work done on the box, you can calculate the work done by both Carol and Bruno separately and then add them together.
First, let's calculate the work done by Carol. The formula for work is W = F * d * cosθ, where W is the work done, F is the applied force, d is the displacement, and θ is the angle between the force and the displacement.
In this case, Carol's force is 11.4 N at an angle of 40.0 degrees downward from the horizontal, and the displacement is 14.5 m. Using the formula, we have:
W Carol = 11.4 N * 14.5 m * cos(40.0°)
Next, let's calculate the work done by Bruno. The setup is similar, but Bruno's force is 11.0 N at an angle of 40.0 degrees above the horizontal.
W Bruno = 11.0 N * 14.5 m * cos(40.0°)
Now, to find the net work done on the box, we add the individual works together:
Net Work = W Carol + W Bruno
Substituting the values, we have:
Net Work = (11.4 N * 14.5 m * cos(40.0°)) + (11.0 N * 14.5 m * cos(40.0°))
Calculating this expression will give you the net work done on the box.
Using a calculator, we find that the net work is approximately 2.49 x 10^2 J (Joules).