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A car travels at a constant speed around a circular track whose radius is 2.5 km. The car goes once around the track in 430 s. What is the magnitude of the centripetal acceleration of the car?

  • Physics -

    The centripetal acceleration is
    a = V^2/R,

    and the velocity V is given by
    2*pi*R = V*P

    where P is the period of 430 s.

    The second equation can be used to eliminate the variable V, leaving you with

    a = [2 pi R/P]^2/R = 4 pi^2 R/P^2

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