Calculate the force of gravatational attraction between two spheres of mass 10.1 kg and 45.4 kg that are 38.5 m apart.

F = G(m1)(m2)/r^2
= 6.67 x 10^-11(10.1)(45.4)/38.5^2
= 2.06 x 10 ^-11 N

Looks good to me

Well, the force of gravitational attraction between two spheres of mass 10.1 kg and 45.4 kg that are 38.5 m apart is approximately 2.06 x 10^-11 N. Just remember, gravity likes to keep things close, but not too close. It's all about balance.

To calculate the force of gravitational attraction between the two spheres, we can use the formula:

F = G(m1)(m2)/r^2

Where:
F is the force of gravitational attraction
G is the gravitational constant (approximately 6.67 x 10^-11 N·m^2/kg^2)
m1 and m2 are the masses of the two spheres
r is the distance between the centers of the two spheres

Given that:
m1 = 10.1 kg
m2 = 45.4 kg
r = 38.5 m

Plugging in these values into the formula:

F = (6.67 x 10^-11 N·m^2/kg^2)(10.1 kg)(45.4 kg)/(38.5 m)^2

Calculating this expression:

F ≈ 2.06 x 10^-11 N

Therefore, the force of gravitational attraction between the two spheres is approximately 2.06 x 10^-11 Newtons.

To calculate the force of gravitational attraction between two spheres, you can use Newton's law of universal gravitation. The formula is:

F = G(m1)(m2) / r^2

Where:
F is the force of gravitational attraction between the two spheres
G is the gravitational constant (approximately 6.67 x 10^-11 N(m^2/kg^2))
m1 and m2 are the masses of the two spheres
r is the distance between the centers of the two spheres

In this case, you have two spheres with masses 10.1 kg and 45.4 kg, and a distance of 38.5 m between their centers. Plugging these values into the formula:

F = (6.67 x 10^-11)(10.1)(45.4) / (38.5)^2
= 2.06 x 10^-11 N

So, the force of gravitational attraction between the two spheres is approximately 2.06 x 10^-11 N.

79.44×10^-11