A 1.00-kg ball is attached to a string of 0.50 m and swung in a horizontal circle with a velocity of 2.00 m/s. Find the centripetal acceleration.
ac=v^2/r
= 2.00^2/.50
= 8.0 m/s^2
That is correct. :-)
To find the centripetal acceleration of the ball, we can use the formula ac = v^2 / r, where ac is the centripetal acceleration, v is the velocity, and r is the radius of the circle.
In this case, the velocity (v) is given as 2.00 m/s and the radius (r) is given as 0.50 m. Substituting these values into the formula, we get:
ac = (2.00 m/s)^2 / 0.50 m
= 4.00 m^2/s^2 / 0.50 m
= 8.00 m/s^2
Therefore, the centripetal acceleration of the ball is 8.00 m/s^2.