The average, that is, the arithmetic mean, age of a group of
doctors and lawyers is 40. If the average age of the doctors is 35
and the average age of the lawyers is 50, then what is the ratio of
the number of doctors to the number of lawyers?
let the number of doctors be d
let the number of lawyers be l
total of ages of doctors = 35d
total of ages of lawyers = 50l
total of both groups = 35d+50l
but this is also equal to 40(d+l)
so 40(d+l) = 35d + 50l
40d + 40l = 35d + 50l
5d = 10l
d/l = 10/2 = 2:1
What is
1 +1000546466
What is
1-1865=
1-32
1+2=
To find the ratio of the number of doctors to the number of lawyers, we need to first find the average age of the group by using the given information.
Let's assume there are 'd' doctors and 'l' lawyers in the group.
We know that the average age of the group is 40, so we can formulate an equation:
(average age of doctors * number of doctors + average age of lawyers * number of lawyers) / (number of doctors + number of lawyers) = average age of the group
Substituting the given values, we have:
(35 * d + 50 * l) / (d + l) = 40
Now, let's simplify this equation:
35d + 50l = 40(d + l)
35d + 50l = 40d + 40l
Now, we can solve this equation for 'l', the number of lawyers:
50l - 40l = 40d - 35d
10l = 5d
l = 0.5d
Therefore, the ratio of the number of doctors to the number of lawyers is 1:2.
This means that for every doctor, there are two lawyers in the group.