I have two problems that I am not sure about how to work out.

1. The distance traveled by a falling object is given by the formula d=4.9t^2, where d is in meters and t is in seconds. Solve the formula for t.

2.The volume of a right circular cone is given by the formula V=1/3(pi)r^2h. Solve the formula for r in terms of V and h.

1. First divide both sides of the equation by 4.9, giving you

0.20408 d = t^2

Then take the square root of both sides of the equation.

2. Multiply both sides by 3/(pi h), giving you
3 V/(pi*h) = r^2
Then take the square root of both sides.

Sure, I can help you with both of these problems.

1. To solve the formula for t in terms of d, we start with the formula d=4.9t^2. The goal is to isolate the variable t on one side of the equation. Here are the steps you can follow:

Step 1: Divide both sides of the equation by 4.9: d/4.9 = t^2.
Step 2: Take the square root of both sides of the equation: √(d/4.9) = t.
Step 3: Simplify the expression as much as possible to get the final answer: t = √(d/4.9).

So, the solution to the equation is t = √(d/4.9).

2. To solve the formula for r in terms of V and h, we start with the formula V=(1/3)πr^2h. The goal is to isolate the variable r on one side of the equation. Here are the steps you can follow:

Step 1: Multiply both sides of the equation by 3: 3V = πr^2h.
Step 2: Divide both sides of the equation by πh: (3V)/(πh) = r^2.
Step 3: Take the square root of both sides of the equation: √((3V)/(πh)) = r.
Step 4: Simplify the expression as much as possible to get the final answer: r = √((3V)/(πh)).

So, the solution to the equation is r = √((3V)/(πh)).