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Physics - Mirrors & Lenses

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When standing 1.25 m in front of an amusement park mirror, you notice that your image is three times taller. What is the radius of curvature of the mirror?

  • Physics - Mirrors & Lenses -

    I will assume it is an upright image, behind the mirror. The distance to the image is di = -3 do because of the 3x magnification, and do = 1.25 m. The minus sign is necessary for upright virtual images.

    The focal length f is given by the equation
    1/do + 1/di = 1/f
    1/1.25 -1/3.75 = 2/3.75 = 1/f
    Therefore f = 1.87 m.

    The radius of curvature is 2f, or 3.75 m. It is a concave mirror; otherwise f would be negative.

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