If a pull back car accelerates from 60 centimeters per second to 100 centimeters per second in 2 seconds,what is the acceleration of the pull back car?
a= change in V/time= (100-60)/2 cm/s^2
idk..thats a toughie..juss use the formula to find acceleration...distance traveled/time taken
To find the acceleration of the pull back car, we first need to calculate the change in velocity and the change in time.
The change in velocity is calculated by subtracting the initial velocity from the final velocity. In this case, the initial velocity is 60 centimeters per second and the final velocity is 100 centimeters per second.
Change in velocity = Final velocity - Initial velocity
= 100 cm/s - 60 cm/s
= 40 cm/s
The change in time is given as 2 seconds.
Now, we can calculate the acceleration using the formula:
Acceleration = Change in velocity / Change in time
Substituting the values:
Acceleration = 40 cm/s / 2 s
= 20 cm/s^2
Therefore, the acceleration of the pull back car is 20 centimeters per second squared (cm/s^2).