In a certain process, 2.11x10^5 J of heat are supplied to a system and at the same time, the system expands against a constant external pressure of 6.89x10^5 Pa. Given that the temperature of the system does not change, find the increase in volume of the system.
Do I need to find work for this? If so, how?
Yes, you need to find the work done by the system in order to find the increase in volume. Work (W) is defined as the product of the pressure (P) and the change in volume (ΔV) of the system. In this case, the pressure is constant, so the work can be calculated using the formula:
W = P * ΔV
Given that the pressure (P) is 6.89x10^5 Pa, you can use this value to find the change in volume (ΔV) by rearranging the formula:
ΔV = W / P
Now, you have the values for heat supplied to the system as 2.11x10^5 J and the pressure as 6.89x10^5 Pa. Plugging these values into the formula, you get:
ΔV = (2.11x10^5 J) / (6.89x10^5 Pa)
Now, simplify by canceling out the units:
ΔV = (2.11 / 6.89) m^3
Finally, perform the calculation to find the increase in volume of the system.