Maths
posted by Mikal .
solve for r
r^641 = 2.5x10^7 (r1)
any ideas?

r1 is a factor of r^64  1 so use synthetic division (notice the pattern) to divide both sides by r1 to get
r^63 + r^62 + ... + r + 1 = 2.5(10)^7
the left side is a geometric series with
a = 1
common ratio = r
n = 64
so the sum of the left side = 1(r^64  1)/63
then (r^63  1)/63 = 2.5(10^7
r^63 = 63(2.5)(10)^7 + 1
taking the 63rd root I got
r = 1.3922 
OOOPS, just looked at my solution again and
I'm WRONG!!! (must have had an early morning synapse collapse)
The sum of my series should have said
1(r^64  1)/(r1)
then r^64  1 = 2.5(10)^7(r1)
which brings me back to what we started with.
Arggh!!!
Sorry, looks like we would have to use some method such as Newtons's Method or some kind of "equation solver" program.
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