Post a New Question


posted by .

Interval 4sec(theta)(sec(theta)+tan(theta))d(theta)

can someone help me start his problem?

  • Calculus -

    Interval, or integral?

    I suggest you split it up into
    4 sec^2 (theta)
    + 4 sin(theta)/cos^2(theta)

  • Calculus -

    You can find the integral of the first one in a table of integrals. The second one is easy if you let u = cos theta and du = -sin theta dtheta

  • Calculus -

    The integral of sec^2 is tan

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question