trig
posted by Rhea .
I am having trouble figuring these two out The directions say find all solutions to the triangles described below. Round each angle to the nearest degree and the length of the missing side to the nearest tenth at the end of the computations
C= 27 degrees 50 minutes, c= 349 m, b=428 m
The second one says
A = 104 degrees, a= .69cm, b=.91 cm
Thanks a lot for the help. These are the last two I need to do.

Do them both the same way. You know an angle and the opposite side. That establishes the ratio
Sin A/a
Use the law of sines
sin A/a = sin B/b = sin C/c
That and the fact that all angles must add up to 180 degrees lets you solve for all unknowns.