Calculus
posted by RJ .
How do we integrate xlne^x .

Calculus 
drwls
ln(e^x) = x, so x(ln(e^x)) = x^2
So just integrate x^2.
Respond to this Question
Similar Questions

calculus help please
dy/dx = 2y^2 Integrating...y=2/3 y^3 + C put 1,1 into the equation, and solve for C. Then find the y for x=2 if y= a^uhttp://math2.org/math/integrals/tableof.htm see exponential functions. dy/dx=2y^2 and if y=1 when x=1, then when … 
Integral calculus
Please do help solve the followings 1) Integrate e^4 dx 2) Integrate dx/sqrt(90^24x^2) 3) Integrate (e^x+x)^2(e^x+1) dx 4) Integrate xe^x2 dx e^4 is a constant. 3) let u= e^x + x du= (e^x + 1)dx 4) let u= x du=dx v= e^x dv= e^x dx 
calculus
1) Integrate (e^x+x)^2(e^x+1) dx 2) Integrate xe^x2 dx Let u=(e^x+x) du=(e^x +1) dx I will be happy to critique your work or thinking. You are posting work for me to do, and I am not inclined to do that, it will not help you for me … 
calculus
1) Integrate Cos^n(x) dx 2) Integrate e^(ax)Sinbx dx 3) Integrate (5xCos3x) dx I Will be happy to critique your thinking on these. 1) Derive a recursive relation. 2) Simplest by replacing sin(bx) by Exp[i b x] and taking imaginary … 
Calculus
How do you integrate [(x^2)(cos(2(x^3)))]? 
Calculus AB
Please help me integrate this equation using partial fractions: Integrate [(x^2+5)/(x^3x^2+x+3)]dx. Thank you very much. 
Calculus
6.] Replace the integral in exercise 5 (int. (1/ 1 – t) dt a = 0, b = 1/2with ? 
calculus 2
Justify, with a written explanation or a mathematical reasoning and with a sketch of at least two different cases, the following properties of integrals: a) If f(x) is less than or equal to g(x) for a<=x<=b then integrate from … 
Calc 1
integrate from 0 to pi/4 (sec^2x)/((1+7tanx)^2)^1/3 integrate form pi^2/36 to pi^2/4 (cos(x^1/2))/(xsin(x^1/2))^1/2 integrate from 0 to pi/3 (tanx)/(2secx)^1/2 
Calculus Indefinite Intergral
I need help with integrating these two problems. Im stuck. 1. integrate (sin^1)dx/((1x^2)^3/2) sin^1 aka arcsin 2. integrate dx/((1x^2)^3/2) by using 1/z Any and all help will be appreciated!