Post a New Question

Physics

posted by .

Given that the Earth's radius is 6.37x10^6 m and taking the earth's gravitational field at its surface to be 9.81N/kg, find the gravitational potential at the Earth's surface.

  • Physics -

    V=G*massearth/r

    Where G*Massearth/r^2=9.81N/kg so
    G*Massearth/r * r=9.81N/kg

    So V= 9.81/r if r is in meters.

    watch the units.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question