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Given that the Earth's radius is 6.37x10^6 m and taking the earth's gravitational field at its surface to be 9.81N/kg, find the gravitational potential at the Earth's surface.

  • Physics -


    Where G*Massearth/r^2=9.81N/kg so
    G*Massearth/r * r=9.81N/kg

    So V= 9.81/r if r is in meters.

    watch the units.

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