16^(d-4) = 3^(3-d) solve for d
log 16^(d-4) = log 3^(3-d) (d-4)log16 = (3-d)log3 expand it dlog16 - 4log16 = 3log3 - dlog3 dlog16 + dlog3 = 3log3 + 4log16 d(log16 + log3) = 3log3 + 4log16 d = (3log3 + 4log16)/(log16 + log3) the rest is button pushing
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