Calculate the value of T delta S (KJ) of reaction for the equation as written. (It is given that the standard enthalpies (J/K mol)are CH3COOH=159.8, O2=205.138, CO2=213.7, H20=69.91)
CH3COOH(l) + 2 O2(g) --> 2 CO2(g) + 2H2O(l)
Something is not right here. Those aren't the number in my table. I don't have CH3COOH but the others are incorrect.
well those are the numbers that was given to me..but im not sure if its called standard enthalpies ..the number are labeled under a "S" with a subscript 0
So is the standard ENTROPY, not enthalpy.
oh sorry my bad...
how would i start this problem?
Look in your problem. There must be a temperature given if you are to calculate TdeltaS.
delta S is calculated by
delta S reaction = (sum of delta S products ) - (sum of delta S reactants). Then T*delta S is just T times that.
my answer is -851.088
is that right?