# Chemistry

posted by .

Antacid neutralizes stomach acid by the following reaction:
Mg(OH)2 + 2HCl -----> MgCl2 + 2H2O
Calculate the amount of Mg(OH)2 (in grams) needed to neutralize 2.5 grams of HCl.

• Chemistry -

how many moles of HCL is 2.5 grams? The balanced equation states it will take half that number of moles of magnesium hydroxide

## Similar Questions

1. ### chemistry

Calcium carbonate CaCO3 reacts with stomach acid (HCl, hydrochloric acid) according to the following equation: CaCO3(s)+2HCl(aq)->CaCl2(aq)+H2O(l)+CO2(g) Tums, an antacid, contains CaCO3. If Tums is added to 35.0 mL of 0.300 M HCl,how …
2. ### Chemistry

Determine how many grams of active antacid ingredient AL(OH)3 would be necessary to neutralize the HCL in 50.0 mL of .0100 M HCL (an approximation of the conc. of HCL in the stomach) 3HCL9aq)+AL(OH)3(s)-> AlCL3 (aq) = 3H2O (L)
3. ### Chemistry

How many grams of calcium carbonate, CaCO3, do you need in an antacid tablet to neutralize 20 mL of stomach acid?
4. ### Chemsitry

Stomach acid is essentially 0.10 M HCl. An active ingredient found in a number of popular antacids is CaCO3. Calculate the number of grams of CaCO3 needed to exactly react with 250 mL of stomach acid. CaCO3(s)+ 2HCl(aq)= CO2(g)+ CaCl2(aq)+ …
5. ### Chemistry

In 1 antacid tab neutralizes 6.84 mmol of HCL (36.46 g/mol). How many tabs are needed to neutralize 125 mL of stomach acid. Assume [H3O+] = 0.10 mmol/mL. I have no idea where to go with this. Any formula would help.
6. ### Chemistry

If 1 antacid tab neutralizes 6.84 mmol of HCL (36.46 g/mol). How many tabs are needed to neutralize 125 mL of stomach acid. Assume [H3O+] = 0.10 mmol/mL. I have no idea where to go with this. Any formula would help
7. ### Chemistry

If Chelcy and Allyson reacted 2.55 grams of Mg with excess hydrochloric acid (HCl), how many grams of MgCl2 will they theoretically produce?
8. ### chemistry

How many grams of Mg(OH)2 are needed to neutralize 55 ml of 0.25 M HCl . according to the following reaction. (show all calculations for credit) Mg(OH)2 (aq) + 2HCl(aq) --- MgCl2 (aq) + 2H2O(l)
9. ### Chemistry

4. A 5.309 g antacid tablet, with CaCO3 as the active ingredient, was mixed was 30.0 mL of 0.831 M HCl. It took 15.3 mL of 0.7034 M NaOH to neutralize the excess acid. a) Calculate the volume of HCl neutralized by the NaOH. b) Calculate …
10. ### chemistry

A 5.309 g antacid tablet, with CaCO3 as the active ingredient, was mixed was 30.0 mL of 0.831 M HCl. After the reaction occurred, it took 15.3 mL of 0.7034 M NaOH to neutralize the excess acid. a) How much HCl (in mL) of was neutralized …

More Similar Questions