algebra
posted by tim .
hey i need some help with a couple of questions please.....
change all bases to 2 then simplify fully
2^n x 4^n+1
8^n2
(note that i cannot put the division line thingo in)
prove that:
a^m/n = n(outside radical sign)a^m (inside radical sign)
i don't know if you can understand that??? if not i will post a link 2 a word doc...
thanx 4 ur help!! :):)

I have a feeling you meant to type
2^n x 4^(n+1) or else the +1 would be a nuisance dangling term
change the last factor
4^(n+1) into [2^2]^(n+1) = 2^(2n+2)
so now you have
(2^n)(2^(2n+2))
= 2^(3n+2) 
thanx,
actually the site cut off my question, what i tried to type was
2^n x 4^(n+1)
/
8^(n2) 
then I am sure you can finish the question if your realize that
8^(n2)
= [2^3]^(n2)
= 2^(3n6) 
thanks for the help, i appreciate it, i was unsure of where iwas going wrong, it was just my brackets i mucked up, thanx.
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