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How many moles of water are produced when 1.05 g of oxygen gas reacts with 1.22 g of hydrogen gas to produce water?

  • chem -

    1.05 g of O2 is 1.05/32 = 0.0328125 moles

    1.22 g of H2 is 1.22/2.016 = 0.60516 moles

    O2 is the limiting reactant. There is more than enough H2 to combine with the available oxygen. Each mole of O2 forms 2 moles of H2O, according to the reaction

    2H2 = O2 -> 2H2O

    Therefore, double 0.0328125 moles
    to get the answer

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