name the following compounds and tell what type of compound they are (binary ionic. ternary ionic, or binary molecular)
a)FeBr3
b)CBr4
c)Na2Cr2O7
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FeBr3 - Iron(III)bromide - binary ionic
CBr4 - Carbon Tetrabromide - binary molecular
Na2Cr2O7 - Sodium dichromate - ternary ionic
a) FeBr3: To name this compound, we need to determine the oxidation states of the elements involved. Iron (Fe) usually forms compounds with a +2 or +3 oxidation state. Bromine (Br) typically has a -1 oxidation state.
Using this information, we can determine that FeBr3 is iron(III) bromide, where Fe is in the +3 oxidation state. Therefore, the compound is a binary ionic compound.
b) CBr4: To name this compound, we need to determine the prefixes for the elements involved. Carbon (C) is a nonmetal, and bromine (Br) is also a nonmetal.
Using the naming rules for binary molecular compounds, we use prefixes to indicate the number of atoms of each element. In this case, 'tetra' indicates four bromine atoms, and 'carbon' indicates one carbon atom. Therefore, the compound is called carbon tetrabromide, and it is a binary molecular compound.
c) Na2Cr2O7: To name this compound, we need to determine the oxidation states of the elements involved. Sodium (Na) usually forms compounds with a +1 oxidation state. Chromium (Cr) can have variable oxidation states, but in this compound, it has a +6 oxidation state. Oxygen (O) typically has a -2 oxidation state.
Using this information, we can determine that Na2Cr2O7 is sodium dichromate, where Cr is in the +6 oxidation state. Therefore, the compound is a ternary ionic compound.